A) His estimate is incorrect, since he has increased a figure to the amount that each employee would receive.
B) Rounded to the nearest dollar, each employee would receive $ 209.
Since a company has $ 6582 to give out in bonuses, and an amount is to be given out equally to each of the 32 employees, and A) a manager, Jake reasoned that since 32 goes into 64 twice, each employee will get about $ 2000 , to determine if his estimate is correct, and B) determine how much will each employee receive, rounded to the nearest whole dollar, the following calculations must be performed:
A)
- 2000 x 32 = 64000
- 200 x 32 = 6400
Therefore, his estimate is incorrect, since he has increased a figure to the amount that each employee would receive.
B)
Therefore, rounded to the nearest dollar, each employee would receive $ 209.
Learn more about maths in brainly.com/question/8865479
I think it is not possible to find a certain equation from just a given points, it must have more given information because there is a lot of parabola pass throw (-1,1).
Answer:
C
Step-by-step explanation:
Quadratic formula is used only to solve the quadratic equations .
Means the equation of the form
In this the x^2 part is must because that only makes the equation a quadratic.
Looking at the four options given to you , only the option C has the missing x^2 term, which makes it a linear equation and hence the quadratic formula cannot be applied there .
So the right option for your question with the quadratic formula is
option
C
Answer: The closest answer I got is 9 5/6 hours
Answer:
69.5%
Step-by-step explanation:
A feature of the normal distribution is that this is completely determined by its mean and standard deviation, therefore, if two normal curves have the same mean and standard deviation we can be sure that they are the same normal curve. Then, the probability of getting a value of the normally distributed variable between 6 and 8 is 0.695. In practice we can say that if we get a large sample of observations of the variable, then, the percentage of all possible observations of the variable that lie between 6 and 8 is 100(0.695)% = 69.5%.
