Question

A website offers a coupon such that each customer has a

Answer 1

Answer:

62.29%

Step-by-step explanation:

The probability of Aya being offered a coupon on at least one of the six days she visits the website is 100% minus the probability that she is not offered a coupon on any of the six days, which is described by a binomial probability with zero successes in six trials with a probability of succes p = 0.15.

$P = 1 - (\frac{6!}{(6-0)!0!}* p^0*(1-p)^{6-0})\\P = 1 - (1* 1*(1-0.15)^{6})\\P=0.6229=62.29\%$

The probability that Aya will be offered a coupon on at least one of the days she visits the website is 62.29%.

Answer 2

Answer:

0.62

Step-by-step explanation:

Let's call

A: Aya gets a coupon one day. P(A) = 0.15

B: Aya doesn't get a coupon one day. P(B) = 1 - 0.15 = 0.85

Aya doesn't get a coupon in any of 6 days  = P(B)^6 = 0.85^6 = 0.38

The probability of Aya getting at least 1 coupon after 6 days is the complement of don't getting any coupon after 6 days, that is:

1 - P(B)^6 =  1 - 0.38 = 0.62