All categories

3 years ago

33762 to the nearest thousand?

Mathematics

2 answers:

Reil [10]3 years ago

8 0

Answer:

34,000

179,400

39,900

Step-by-step explanation:

In the number 33,762, the 3 is in the thousands place, so we look to the number behind it. If it is less than 5, we round down, and if it is more than 5 we round up.

Since 7 is more than 5, we round up, so our rounded number would be

34,000

Let’s use this logic for the rest of these numbers

179,406

4 is in the hundreds

Previous number in 0 which is less than 5, so it rounds down

179,400

39,994

9 is in the tens place

Previous number is 4 which is less than 5, so it rounds down

39,990

Andreas93 [3]3 years ago

7 0

Step-by-step explanation:

1) 34,000

2)179,400

3) 40,994

1) the idea is to look at the 1,000ths place (33,762) bcause the #after is 762, the 7 is larger than 5, therefore, u make 33,000 into 34,000.

2) same with #2, bcause your rounding 2 the nearest 100th, 406 is closer to 400 than, 500..

try 2 remember, your place-marks...hope I'm helping...

You might be interested in

At noon on tuesday in Chicago the temperature in degrees Fahrenheit was -2 Fahrenheit at noon on Wednesday the temperature was 8

bagirrra123 [75]

The temperature was 6 degrees Fahrenheit

4 0

3 years ago

Read 2 more answers

Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit

Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is $2$

Part 2) The vertex is the point $(1,8)$

Part 3) The equation of the axis of symmetry is $x=1$

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is $y=2x^{2}-4x+10$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

$x=h$

In this problem we have

$y=2(x-1)^{2}+8$ -----> this is the equation in vertex form of a vertical parabola

The value of $a=2$

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point $(1,8)$

$(h,k)=(1,8)$

The equation of the axis of symmetry is $x=1$

The equation of a vertical parabola in standard form is equal to

$y=ax^{2}+bx+c$

Convert vertex form in standard form

$y=2(x-1)^{2}+8$

$y=2(x^{2}-2x+1)+8$

$y=2x^{2}-4x+2+8$

$y=2x^{2}-4x+10$

see the attached figure to better understand the problem

7 0

3 years ago

The graph of the w=equation x+3y=6 intersects the y axis at the point whose coordinate are

nevsk [136]

Y intercept = when x = 0
Plug in x = 0
0 + 3y = 6
3y = 6, y = 2

Solution: a, (0,2)

8 0

3 years ago

Correct/best answer will get brainliest!

vodka [1.7K]

The answer would be b.100 because its clearly not a right triangle

6 0

4 years ago

2. The electrical resistance R of a wire varies inversely with the square of its diameter d. If a wire with a

Mariulka [41]

Answer:

$0.225 \Omega =225 m\Omega$

Step-by-step explanation:

We know (Ohm second law) that $R= \frac{k}{d^2}$ where k inlcudes the rest of the parameters (material, lenght). In our situation we have k= $0.4\cdot9 \Omega mm^2$ . The moment the diameter becomes 8mm R becomes

$R= {{0.4\cdot 9}\over{16}} \Omega = 0.225 \Omega$

4 0

3 years ago