Log x+ log 7= log 42
log x=log 42 - log 7
log x=log 42/7 [ log a - log b= log (a/b) ]
log x= log 6
therefore:
x=6
Answer: x=6
How comfortable are you writing this whole paragraph goddam I could never divide 100
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Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Answer:
x =10
Step-by-step explanation:
7(3x-1)-(x+5)
21x-7-x+5
20x-2=-52
x=20÷2