Answer:
Step-by-step explanation:
so
hope this helped! :)
<span>When 20 is increased by 30% of itself
</span><span>When 20 is added to by (30% OF 20)
</span><span>
20 + (30% x 20)
</span><span>20 + (0.3 x 20)
</span><span>
20 + (6)
</span>26
Answer:
20.27
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, the sample means with size n of at least 30 can be approximated to a normal distribution with mean and standard deviation 
Using the Central Limit Theorem for Means, what is the standard deviation for the sample mean distribution?
This is s when 
. So
So the correct answer is:
20.27
Answer:
I believe the equation would be n - 2 = -15.
Step-by-step explanation:
"4 less than a number (n)" is subtraction. You can write it as "n minus 4". "is -15" means this is the difference. This can also be written as "equals -15".
n - 4 = -15
Hope this helps,
♥<em>.A.W.E</em><u><em>.S.W.A.N.</em></u>♥
We have that
<span>question 1
Add or subtract.
4m2 − 10m3 − 3m2 + 20m3
=(4m2-3m2)+(20m3-10m3)
=m2+10m3
the answer is the option
</span><span>B: m2 + 10m3
</span><span>Question 2:
Subtract. (9a3 + 6a2 − a) − (a3 + 6a − 3)
=(9a3-a3)+(6a2)+(-a-6a)+(-3)
=8a3+6a2-7a-3
the answer is the option
</span><span>B: 8a3 + 6a2 − 7a + 3
</span><span>Question 3:
A company distributes its product by train and by truck. The cost of distributing by train can be modeled as −0.06x2 + 35x − 135, and the cost of distributing by truck can be modeled as −0.03x2 + 29x − 165, where x is the number of tons of product distributed. Write a polynomial that represents the difference between the cost of distributing by train and the cost of distributing by truck.
we have that
[</span>the cost of distributing by train]-[the cost of distributing by truck]
=[−0.06x2 + 35x − 135]-[−0.03x2 + 29x − 165]
<span>=(-0.06x2+0.03x2)+(35x-29x)+(-135+165)
=-0.03x2+6x+30
the answer is the option
</span><span>C: −0.03x2 + 6x + 30
</span><span>
</span>
