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Volgvan
3 years ago
11

Which expression has the least value when x = 100?

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

The answer is 1-x

zmey [24]3 years ago
3 0

Answer:

The answer is .................   1 - x                                                                                      

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lys-0071 [83]

Answer:

Pull terms out from under the radical, assuming positive real numbers.

Exact Form:

26-5√5

Decimal Form:

14.81966011...

7 0
3 years ago
Louis, Lucas, Garcelle, and Sheryl go bowling every week. when ordere for highest to lowest, how many ways can their scores be a
vichka [17]
Since lucas is never first and garcelle always beats louise it could be garcelle, louise then lucas or garcelle lucas louise 2 options

5 0
3 years ago
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Sorry I dont know this answer
7 0
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Lotteries are an important income source for various governments around the world. However, the availability of lotteries and ot
SashulF [63]

Answer: 0.0473

Step-by-step explanation:

Given : The proportion of gambling addicts : p=0.30

Let x be the binomial variable that represents the number of persons are gambling addicts.

with parameter p=0.30 , n= 10

Using Binomial formula ,

P(x)=^nC_xp^x(1-p)^{n-x}

The required probability = P(x>5)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\=^{10}C_6(0.3)^6(0.7)^{4}+^{10}C_7(0.3)^7(0.7)^{3}+^{10}C_8(0.3)^8(0.7)^{2}+^{10}C_9(0.3)^9(0.7)^{1}+^{10}C_{10}(0.3)^{10}(0.7)^{0}\\\\=\dfrac{10!}{4!6!}(0.3)^6(0.7)^{4}+\dfrac{10!}{3!7!}(0.3)^7(0.7)^{3}+\dfrac{10!}{2!8!}(0.3)^8(0.7)^{2}+\dfrac{10!}{9!1!}(0.3)^9(0.7)^{1}+(1)(0.3)^{10}\\\\=0.0473489874\approx0.0473

Hence, the required probability = 0.0473

5 0
3 years ago
In a bag of trail mix, there are 5 cups of nuts for every 2 cups of chocolate candies. If there are 12 cups of nuts in a bag of
Katyanochek1 [597]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
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