From 100 to 80 is 8/10, so the recursive formula is
an=a(n-1)*1/8
or
an= a1*1/8(n-1)
an=a1*(n-1)/8
Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy = 
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) =
- 
⇒ x + iy = 
⇒ x + iy =
[ ∵
]
⇒ x + iy =
⇒ x + iy =
⇒ x + iy =
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
The answer and working are shown in the photo below
First, find 3/4 of 24. 24/4=6, 6x3= 18. Now, find 1/9 of 18. 18 divided by the denominator, 9, is 2. Since the numerator is one, our answer remains as 2. So yeah, the answer is 2.