Question

Help I need help ON THISSSS

Answer 1

Answer:

3. 147 $ft^{3}$  4. $\frac{160}{3} \pi$ $ft^{3}$

Step-by-step explanation:

3. Volume of a square pyramid = $(base.edge.length)^{2}$ × $\frac{height}{3}$

Variables:

V = volume

x = base edge length

h = height

V = $x^{2}$  × $\frac{h}{3}$

x = 7 ft

h = 9 ft

Plug the values in the equation:

V = $7^{2}$ × $\frac{9}{3}$

V = 49 × 3

V = 147 $ft^{3}$

4. Volume of cone = $\pi r^{2} \frac{h}{3}$

Variables:

V = volume

r = radius

h = height

V = $\pi r^{2} \frac{h}{3}$

r = 8ft /2 = 4 ft (radius is half of the diameter)

h = 10 ft

V =  $\pi 4^{2} \frac{10}{3}$

V = $\pi$ × 16 × $\frac{10}{3}$

V = $\frac{160}{3} \pi$ $ft^{3}$

Answer 2

Answer:

ms girll i think you multiply