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3 years ago

PLEASE ANSWER CORRECTLY WILL GIVE 15 PTS! Solve each of the following inequalities.

Mathematics

1 answer:

Kitty [74]3 years ago

5 0

Answer:

a. k > 7

b. a < -21

c. h > 9

d. f < 301

Step-by-step explanation:

a. 2k + 7 > 21

2k > 14

k > 7

b. a/3 + 12 < 5

a/3 < -7

a < -21

c. 6h − 5 > 49

6h > 54

h > 9

d. f/7 − 9 < 34

f/7 < 43

f < 301

Hope this helps!

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Answer:

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Step-by-step explanation:

the quadratic equation can be written as (x-root1)(x-root2)

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x² -(5/2)x +3xi -(5/2)x + 25/4 -(15/2)i -3xi +(15/2)i -9i², simplify

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7 0

3 years ago

13x−6y=22 x=y+6 whats the answer

Vikentia [17]

Answer:

x = -2 y = -8

Step-by-step explanation:

13x - 6y = 22

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6(x-y) = 6*6

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3 years ago

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2 years ago

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Lelechka [254]

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Step-by-step explanation:

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3 years ago

The Key Club is having a fundraising dinner for charity. The venue that holds a maximum of 500 people will

Alexus [3.1K]

Answer:

$\dfrac{\$1000+\$20x}{x} \leq \$25$

Minimum 200 people other than the 2 charity representatives.

Step-by-step explanation:

Given that:

The venue can hold a maximum of 500 people.

Cost of venue = $1000

Per person cost for food = $20

Two charity representatives get to attend the dinner for free.

To find:

The inequality and to determine how many people must come to keep costs at most $25.

Solution:

Let the number of people attending the dinner = $x$

Cost of food for $x$ people = $\$20x$

Total cost = $1000 + $\$20x$

Cost per person = Total cost divided by Number of people attending the dinner.

As per question statement:

$\dfrac{\$1000+\$20x}{x} \leq \$25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200$

Therefore, the answer is:

Minimum 200 people other than the 2 charity representatives should attend the dinner.

8 0

3 years ago