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4 years ago

Hurry please help me!

Mathematics

1 answer:

Dennis_Churaev [7]4 years ago

5 0

Answer:

d. 23

Step-by-step explanation:

Let the number of cars be x and buses be y

Then we have below inequalities as per given:

5x + 32y ≤ 1310
x + y ≤ 135

It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income

Let's assume there are 135 cars and buses, then from the second inequality:

x = 135 - y

Substitute it in the first one:

5(135 - y) + 32y ≤ 1310
675 - 5y + 32y ≤ 1310
27y ≤ 1310 - 675
27y ≤ 635
y ≤ 635/27
y≤ 23.5

The greatest number of buses is 23

Option D. 23 is correct

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