Answer:
Step-by-step explanation:
Let the number of cars be x and buses be y
<u>Then we have below inequalities as per given:</u>
- 5x + 32y ≤ 1310
- x + y ≤ 135
It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income
<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>
<u>Substitute it in the first one:</u>
- 5(135 - y) + 32y ≤ 1310
- 675 - 5y + 32y ≤ 1310
- 27y ≤ 1310 - 675
- 27y ≤ 635
- y ≤ 635/27
- y≤ 23.5
The greatest number of buses is 23
Option D. 23 is correct
