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vodka [1.7K]
3 years ago
11

Hurry please help me!

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

  • d. 23

Step-by-step explanation:

Let the number of cars be x and buses be y

<u>Then we have below inequalities as per given:</u>

  • 5x + 32y ≤ 1310
  • x + y ≤ 135

It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income

<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>

  • x = 135 - y

<u>Substitute it in the first one:</u>

  • 5(135 - y) + 32y ≤ 1310
  • 675 - 5y + 32y ≤ 1310
  • 27y ≤ 1310 - 675
  • 27y ≤ 635
  • y ≤ 635/27
  • y≤ 23.5

The greatest number of buses is 23

Option D. 23 is correct

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