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ratelena [41]
2 years ago
6

The midpoint of JK¯¯¯¯¯¯¯¯is M(6, 3). One endpoint is J(14, 9). Find the coordinates of endpoint K.

Mathematics
1 answer:
maxonik [38]2 years ago
4 0
The image is downloaded.

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A rectangle has a width of 9 inches. The area of the rectangle is 648 square inches. What is the length, in inches, of the recta
Ivan

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Step-by-step explanation:

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7 0
3 years ago
-7r^2= -329 square root property​
Genrish500 [490]

9514 1404 393

Answer:

  r = ±√47

Step-by-step explanation:

  -7r^2 = -329 . . . . given

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2 years ago
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Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1
Margaret [11]

we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Here we are given the equation:

x^2 + y^2 + 10x - 1 = 0

Completing squares, we get:

x^2 + 10x + y^2 = 1

Now we can add and subtract 25 to get:

x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

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2 years ago
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