In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?

Answer:

The probability is $P(g) =0.72$

Yes the result is reasonably close

Step-by-step explanation:

From the question we are told that

The number of of green peas is $g = 436$

The number of yellow peas is $y = 171$

The sample size is $n = 171 + 436 = 607$

The probability of getting an offspring pea that is green is mathematically represented as

$P(g) = \frac{g}{n}$

$P(g) = \frac{436}{607}$

$P(g) =0.72$

Comparing $P(g) =0.72$ to $\frac{3}{4} = 0.75$ we see that the result is reasonably close

7 0

3 years ago

Write an expression that, when simplified is equivalent to 15x +7

cupoosta [38]

Answer:

2(7.5x+3.5)

Step-by-step explanation:

I can't remember what these equations are actually called, however in order to solve this you simply multiply 7.5 by 2, and then 3.5 by 2.

4 0

3 years ago

If 3 equals x over 3.3 what is x

Nana76 [90]

It’s 9.9 because 3 times 3.3 is 9.9

3 0

3 years ago

Please help me with this question I’m so confused

zavuch27 [327]

$s = ut + \frac{1}{2} a {t}^{2} \\ s = 10( \frac{1}{2} ) + \frac{1}{2} ( - 2) {( \frac{1}{2}) }^{2} \\ s = 10( \frac{1}{2} ) + \frac{1}{2} ( - 2)( \frac{1}{4} ) \\ s = 5 + ( - 1)( \frac{1}{4} ) \\ s = 5 + ( - \frac{1}{4} ) \\ s = 5 - \frac{1}{4} \\ s = \frac{20}{4} - \frac{1}{4} \\ s = \frac{19}{4}$

Hope it helps

Please give brainliest

4 0

2 years ago

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