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Brrunno [24]
3 years ago
15

Who shall help meh today?

Mathematics
2 answers:
Wittaler [7]3 years ago
7 0

Answer:

If I am correct they should all go to across each other because if you think about it they all lead to the explanation be asked for hope this helped and hopefully is correct

Step-by-step explanation:

Andrej [43]3 years ago
6 0
Actually that’s the wrong answer!!! Here’s the right ones: hope you didn’t submit!!

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Write an algebraic expression 3 more than twice a number​
kati45 [8]

Answer:

2x+3

Step-by-step explanation:

Let x be the number

twice a number

2x

3 more than

2x+3

5 0
3 years ago
HELPPP IM STUCK ON THIS
Shalnov [3]

Answer:

10-10

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A video game is on sale for 20% off. The sale price of the game is $35.00. How much did the game ORIGINALLY cost?
Elena-2011 [213]

Answer:

$43.75

Step-by-step explanation:

To find how much the game would have been 20% off from 43.75, you would have needed the expression

43.75*0.8

So to go from 35 to 43.75, you need the expression

35/0.8.

This expression in simpler terms means What is 38, 80% of?

That is how we get 43.75.

35/0.8 = 43.75.

7 0
3 years ago
The ratio of Adams books to Brandon's books is 5:4. The ratio of Brandon's books to Colins books is 3:2. Colin has 56 books. How
Phoenix [80]

Answer

112 Adam's book

7 0
3 years ago
Solve the following question
White raven [17]

Answer:

g) u^{4}\cdot v^{-1}\cdot z^{3}, h) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}}

1) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}} Given

2) \frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} } Definition of division

3) \frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}   \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)  Associative property

5) u^{4}\cdot v^{-1}\cdot z^{3}   \frac{a^{m}}{a^{n}} = a^{m-n}/Result

h) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}

1) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10} Given

2) \frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} } Definition of division

3) \frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}  \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) } Factorization/Distributive property

5) \left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right] Modulative and commutative properties/Associative property

6) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}  \frac{a^{m}}{a^{n}} = a^{m-n}/\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}/Definition of division/Result

3 0
3 years ago
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