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sladkih [1.3K]
2 years ago
5

Which solution set is graphed on the number line?

Mathematics
2 answers:
Zolol [24]2 years ago
8 0

Answer:

C. x is less then or equal to 1

Step-by-step explanation:

I just took the unit test on edu I got 88.

Burka [1]2 years ago
5 0
I think C but I’m not sure
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8 (40+7) = ( 8. ) + (8 7
prohojiy [21]
The first part is 8 x 40=320
8 x 7=56
320+56 and i am not sure what you have going on on the other half
8 0
3 years ago
The circumference of a circular pond is 654 feet.Whats the diameter at a rate of 6 feet per second?
Alex73 [517]
<span>To find the answer we need to find the raduis

Circumference = 2πr
r=</span>\frac{Circumference}{2 \pi }
r=\frac{654}{2 \pi }
 = 104.08

The diameter is 2r, hence the diameter is 208.16

If the rate to cross is 6ft. per second, time can be found by dividing the raduis by 6

It would take 34.7 seconds
8 0
3 years ago
A line through which two points would be parallel to a line with a slope of 3/4?
Mumz [18]

Answer:

F. (0, 5) and (-4, 2)

Step-by-step explanation:

We need to calculate the slope of each of the given sets of points until we find the set associated with a slope of 3/4:

F. (0,5) and (-4,2) As we go from (-4, 2) to (0,5), x increases by 4 and y increases by 3, so the slope is m = rise / run = 3/4. This is the line with slope 3/4.

5 0
2 years ago
Kendra flips a coin 3 times what is the probability that she flips tails all 3 times
Softa [21]
She has a 50 percent chance she flips the coin on tails.
5 0
3 years ago
Please answer ASAP
labwork [276]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

A 12 cm cone with a dome on top of it that has an 8 cm diameter

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cone volume)

V = \dfrac{ \pi *r^2*h}{3}

V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}

V = 3.14*16*4

\boxed{V = 200.96\:cm^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{4^3}{3}

V = 2*3.14 * \dfrac{64}{3}

V = \dfrac{401.92}{3}

\boxed{ V_{hemisphere} \approx 133.97\:cm^3}

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

\boxed{\boxed{\boxed{Volume\:of\:the\:figure = 334.93\:cm^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

6 0
3 years ago
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