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3 years ago

5

Which solution set is graphed on the number line?

2 answers:

Zolol [24]3 years ago

8 0

Answer:

C. x is less then or equal to 1

Step-by-step explanation:

I just took the unit test on edu I got 88.

Burka [1]3 years ago

5 0

I think C but I’m not sure

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Which graph represents y = cosine (2 x minus pi) + 5?

Artyom0805 [142]

Answer:

A

Step-by-step explanation:

edgenuity

5 0

3 years ago

DUE TODAY SOMEONE HELP ME!!!!!!!!! When solving an equation with an exponent that is a variable can I ONLY distribute the number

DIA [1.3K]

Answer:

<em>Option C</em>

Step-by-step explanation:

If we were to consider this question as a whole, all we are being asked is to find an expression equivalent to 2 * ( 5 )^x, as all other function are expressed in the same f ( x ) format. Now all we have to thing about are the expression that = 2 * ( 5 )^2x;

$2( 5 )^2x =\\2( 5^2 )^x =\\2( 25 )^x\\\\Solution - Option C$

Hope that helps!

8 0

3 years ago

The center of an ellipse is (-9,3). one focus is (-7,3). The major axis is 24 units long. What is the equation of the ellipse in

CaHeK987 [17]

Answer:

$\frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

Step-by-step explanation:

The standard equation of the ellipse is

$\frac{(x-\alpha)^2}{a^2}+\frac{(y-\beta)^2}{b^2}=1\;\cdots(i)$

where, $(\alpha, \beta)$ is the center and a,b are semi axes of the ellipse along x-axis and y-axis respectively.

Given that, $(\alpha, \beta)=(-9,3)$ and major axis, $2a=24$ .

So, semi major axis, $a=24/2=12$ .

Now, focus of the ellipse is (-7,3).

Let $e$ be the eccentricity of the ellipse,

So, $e=\frac c a$

where $c$ is the distance between the center and focus of the ellipse.

By using the distance formula,

$c=\sqrt{(-9-(-7))^2+(3-3)^2}=2$

$\Rightarrow e=\frac {2}{12}=\frac{1}{6}\;\cdots(ii)$

Again, the relationship among $a,b$ and $e$ is

$e=\sqrt{1-\frac{b^2}{a^2}$

$\Rightarrow \frac{1}{6}=\sqrt{1-\frac{b^2}{(12)^2}$ [from equation (ii)]

$\Rightarrow \frac{1}{36}=\sqrt{1-\frac{b^2}{144}$ [squaring on both the sides]

$\Rightarrow \frac{b^2}{144}=1-\frac{1}{36}$

$\Rightarrow b^2=\frac{35}{36}\times144=140$

So, the value of square of semi-minir axis, $b^2=140$ .

Hence, from equation (i), the equation of required ellipse is standard form is

$\frac{(x-(-9))^2}{144}+\frac{(y-3)^2}{140}=1$

$\Rightarrow \frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

8 0

3 years ago

An artist is creating a stained glass design. She uses a lead border around each piece. The radius of the circle is 2 ¼ in. Use

NARA [144]

Answer:

The correct answer is -

a. 4.5 inches.

b. side or arm (a)

c. (a) or 4.5, and 18

d. (d) 4.5, and 14.1428

e. 22/7 × r^2 = 15.90

Step-by-step explanation:

Given :

Radius or r = 2 ¼ inches

Solution:

a. the diameter of the circle -

d = 2r

= 2 ¼ *2

= 2.25*2

= 4.5

b. The diameter of the circle is the same length as one side or arm of the square which is

a = d = 4.5

c. The perimeter of the square

P = 4a = 4d = 4*4.5 = 18

d. Perimeter of the circle =

2πr = πd = (22/7)*4.5

= 14.1428

e. the area of the circle =

22/7 × r^2

= 15.90

4 0

3 years ago

Joe and Janna leave home at the same time, traveling in opposite directions. Joe drives 45 mph and Janna drives 40 mph. In how m

Nataly [62]

510 = 45x + 40x
510 = 85x
Divide by 85
6 = x

6 hours

3 0

3 years ago

Read 2 more answers