Question

What is the equation for g, which is f(x) = 2x2 + 3x − 1 reflected across the y-axis? Group of answer choices g(x) = −2x2 − 3x − 1 g(x) = 2x2 + 3x − 1 g(x) = −2x2 − 3x + 1 g(x) = 2x2 − 3x − 1

Answer 1

Answer:

$g(x) = 2x^2 - 3x - 1$

Step-by-step explanation:

Given

$f(x) = 2x^2 + 3x - 1$

Required

Determine g(x), if f(x) is reflected across the y axis

When a function (x,y) is reflected across the y axis, the new function becomes (−x,y).

In other words,

$g(x) = f(-x)$

Calculating f(-x)

$f(-x) = 2(-x)^2 + 3(-x) - 1$

$f(-x) = 2x^2 - 3x - 1$

Substitute g(x) for f(-x)

$g(x) = 2x^2 - 3x - 1$

Hence;

$g(x) = 2x^2 - 3x - 1$