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olya-2409 [2.1K]
2 years ago
14

Golf balls cost $0.90 each at Jerzy’s Club, which has an annual $25 membership fee. At Rick and Tom’s sporting-goods store, the

price is $1.35 per ball for the same brand. Where you buy your golf balls depends on how many you wish to buy. Explain, and illustrate your reasoning with a graph.
Mathematics
1 answer:
taurus [48]2 years ago
5 0

Answer:

See attached graph.

Step-by-step explanation:

Each situation can be expressed as an equation:

<u>Jerzy: </u> Total Cost (y1) is the $25 membership fee plus $0.80/golf ball (x):

y1 = $25 + $0.90x

<u>Rick and Tom's:</u>  Total Cost (y2) is $1.25 per golf ball, x.

y2 = $1.25x

See the attached graphs of these two equations.  Jerzy's cost less after 56 balls are purchased.

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vazorg [7]

Answer:

y = 0.5x + 2

My graph looks like this:



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3 years ago
What’s the answer to this problem?
Allisa [31]
We can start to solve this problem by using what we know. The recipe calls for 2/3 cup of flour per 1/4 batch of cookies. Now, If we want to write the rate as a complex fraction, we can replace the per with a division sign. This makes it become (2/3)/(1/4) or 
\frac{  \frac{2}{3} }{  \frac{1}{4} } 
5 0
3 years ago
Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a
evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1=\frac{1}{2} *PQ*RM

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=\frac{1}{2} *SR*PN

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=\frac{1}{2}*PQ*h

S2=\frac{1}{2}*SR*h

Adding them together, we get the area of the whole trapezoid:

S=S1+S2=\frac{1}{2} (PQ+SR)h,

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}

Simplifying, we have

=>A= \frac{ah+2b_{1+C} }{2}

Factoring we have,

=> A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2}  \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}

 But, a+ b_{1} + c  is equal to b_{2}, the longer base of our trapezoid.

Hence, A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}

We have discussed two ways by which we can derive area of a trapezoid.

Read to know more about Trapezoid

brainly.com/question/4758162?referrer=searchResults

#SPJ10

5 0
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Which algebraic expression represents this phrase? the product of 40 and the distance to the finish line A. 40•d B.
kenny6666 [7]

Answer:

A 40•d

Step-by-step explanation:

The product of 40 and the distance (d)

40•d

B is division

C is subtraction

D is addition

The product of two numbers is multiplication, so the answer must be A

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3 years ago
(2x^2+5x-7)+(3-4x^2+6x)
jarptica [38.1K]
-2x^2 + 11x - 4

To get this answer, you need to combine like terms. However, before this, remember that you are ADDING, so don’t accidentally subtract any numbers.

Then, just follow these steps:

2x^2 + (-4x^2) = -2x^2

5x + 6x = 11x

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And proceed to put them in the equation correctly.

Hope this helps!
6 0
3 years ago
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