We know that
in the right triangle ACD
Applying the Pythagoras theorem
AC²=AD²+CD²------> AD²=AC²-CD²-----> AD²=5²-4²---> AD²=9----> AD=3
let
∅=angle CAD
tan ∅=4/3
in the right triangle CDB
the angle DCB is equal to ∅
tan ∅=DB/CD-------> DB=CD*tan ∅------> DB=4*(4/3)----> DB=16/3
AB=AD+DB-----> 3+16/3----> AB=25/3----> AB=8.33
the answer is
<span>b. 8.3</span>
Answer:
a. what is the perimeter of a square with side length:
3 cm=12cm
7 cm=28
b.90
Draw a square with 4 equal sides that are 6 inches long. Then draw a small square on a corner of your drawn square. A(x) = 36 - A^2
a being the area of the smaller square
A^2= area of a square.
15 - 3/4x = -9
-3/4x +15 = -9
-3/4x = -24
(-3/4x) * (4/-3) = (4/-3) * -24
x = 32
