<h2>Answer</h2>
The amount that will be financed: $9500
The total amount of the monthly payments: $10,800
The amount of the finance charge: $1,300
<h2>Explanation</h2>
Remember that the down payment is the initial amount you paid to reduce the amount you finance.
Given that, the amount that Jim will finance will be the price of the bath in cash minus the down payment:
Amount that will be financed = $12,000 - $2,500 = $9500
Next, to find the total amount of the monthly payments, we just need to multiply the monthly payment by the total number of monthly payments:
Total amount of the monthly payments = $450.00*24 = $10,800
Finally, to find the financial amount, we just need to subtract the financed amount from the total amount of the monthly payments:
Amount of the finance charge = $10,800 - $9500 = $1,300
Answer:
D.) (5,31)
Step-by-step explanation:
Since they already gave you the value of x
plug that into the equation for y
y=6(x)+1
y=6(5)+1
y=30+1
y=31
Therefore, you have
x=5 and y=31
(5,31)
HOPE THIS HELPS!
Answer:
0 is your answer
Step-by-step explanation:
Answer:
(a) d = 0.012v^2
(b) 4.8 m
(c) 25 m/s
Step-by-step explanation:
(a) Writing an equation to fit a bunch of data is often a matter of trial and error. You can often get an idea of the sort of function that is involved by graphing the data points.*
When we do that, we see the relationship is non-linear with an upward curvature. It might be described by a polynomial or exponential function.
When we try a quadratic equation, we find the fit is really quite good. The graphing calculator that does this quadratic regression analysis tells us the equation is essentially ...
d = 0.012·v^2
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(b) The equation predicts a depth of 4.8 m.
d = 0.012·20^2 = 4.8
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(c) Solving for speed, we get a speed of 25 m/s.
7.5 = 0.012v^2
625 = v^2 . . . . . . divide by .012
25 = v . . . . . . . . . take the square root
_____
* The energy of a falling object is proportional to the square of its speed. If we assume that the depth of penetration into the clay is proportional to the energy absorbed, then it is not surprising to see a quadratic relationship between speed and distance. What is surprising is that this relationship would show up in middle school math problem, not a high-school physics problem.
Essentially, you have to assume the form of the equation, then find the coefficients that make it so. Working with the evenly spaced table values of 5, 10, 15 m/s can simplify the effort.
A graphing calculator or spreadsheet can do the bulk of the work once the data is entered.