One way to look at it would be to solve for y - if what x is multiplied by is the same for both sides, they're parallel. If one is the negative reciprocal (e.g. for 5/6 the reciprocal is 6/5 and the negative reciprocal is therefore -6/5) of another, they're perpendicular and if they're neither they're neither.Solving for y in x+5y=4, we can subtract x from both sides to get 5y=-x+4. Next, we can divide both sides by 5 to get -x/5+4=y. Since -x/5=(-1/5)(x) and -1/5 is not the negative reciprocal of 5/6 as established earlier, they are neither
Answer:
22 assuming the * was a mistake im not sure if u meant the * if u did mean in what does it mean
Step-by-step explanation:
Answer:
3x+y
Step-by-step explanation:
It's already in simplest form, you can't do anything else to it.
Answer:
Yes
With an extra 3000CHF
Step-by-step explanation:
In year 2005, the exchange rate was 1$ = 1.15CHF
The student came in with $20,000.
The amount he had in CHF(swiss franc) = ?
$1 = 1.15C
$20,000 = x CHF
X = (20000 × 1.15) / 1
X = 23,000CHF
When he came to Zürich in 2005, he has 23,000 swiss franc.
But the exchange rates changed in 2006 to C1.30 against the dollar.
$1 = 1.30CHF
$20,000 = xCHF
X = 26,000CHF
In 2006, he would've had 26,000CHF.
The difference between what he would've had in 2006 against 2005 is
26,000CHF - 23,000CHF = 3000CHF
He would've had an extra 3000CHF if he came in the year 2006.