Ask question

Ask question

All categories

2 years ago

7

The Math 123 book includes about 230 pages (not including the back parts of the book). If you aim to complete 65% of all the pag

es, how many should you finish?

1 answer:

alina1380 [7]2 years ago

8 0

Answer: 150 pages

Step-by-step explanation:

I usually just multiply the number by the percentage and it works out just fine :)

You might be interested in

Find the missing value: x2 (squared) = 625 5 10 25 50

Alona [7]

$\bf x^2=625\implies x=\sqrt{625}\implies x=25$

5 0

3 years ago

Read 2 more answers

What is u equal to u=?

Jet001 [13]

Answer:

u= -449

Step-by-step explanation:

714=6(u+629)-366

<u>+366 +366</u>

1080=6u+3774

<u>-3774 -3774</u>

6u=-2694

<u>÷6 ÷6</u>

u=-449

6 0

3 years ago

6. Select all the expressions that are equivalent to 10-6. 1 a. 1000000 b. 1000000 1 C. 106 d. 108 . 10-2 6 10 e. 10 1 f. 10-10-

zhuklara [117]

N/A

Step-by-step explanation: Just pay attention Haden

7 0

3 years ago

Dimitri earns $4.50 for each box of fruit picked

Gemiola [76]

A) $90
b) 33.34 (round to 34 if you need a solid number)
c) $13.50 an hour

5 0

2 years ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, <u>2 is our minimum and 17 is our maximum.</u>

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

<u>The median is 12.5.</u>

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

<u>The first quartile is 6.</u>

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

<u>The third quartile is 15.</u>

3 0

2 years ago