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Blizzard [7]
3 years ago
9

What is the image point of (3,-8) after a translation left 2 units and up 5 units?

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0
The new image point will be at (1,-3)
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Can I please get help with number 23 am stuck.
denpristay [2]

Answer:

B

Step-by-step explanation:

Use the elimination method by adding the equations together:

5x - 2y = 4

3x + 2y = 12

---> 8x = 16

x = 2

6 0
3 years ago
NEED HELP URGENT!! :))))
bija089 [108]

Answer:

18 cm²

Step-by-step explanation:

Base * half height says 6*6/2 = 18.

The trick is to put the 90° angle at the base (rotate the triangle).

4 0
4 years ago
Read 2 more answers
I dont know how to solve these
Ne4ueva [31]

Answer:

137°

Step-by-step explanation:

So, both are equal to each other due to them being the same degree angle.

5x+7=8x-71

subtract 5x on both sides

7=3x-71

add 71 to both sides

77=3x

divide both sides by 3

77/3=x

x equals about 26

insert x into the problems

[5(26)+7]°

this equals 137°

[8(26)-71]°

this equals 137°

7 0
4 years ago
Draw the line passing through the point (3,-4) with a slope of 2/3
AleksAgata [21]
You just find the coordinate point. then, use your slope 2/3 (up 2, right 3) :)

EX: if your slope was negative, you’d do the same thing, but opposite -2/-3 (down 2, left 3)

hopefully this helps, good luck with math!! <3

(ps sorry if the drawing bothers you, but I wanted to show you as best as I could on how to solve your question :) )

5 0
3 years ago
1-cos2a/1+cosa if 1/3 how much sin²a
Helen [10]

Answer:

(1-cos2A) /(1+cos2A) =tan²A

Proof:

We know that,

cos(A+B) =cosA.cosB-sinA.sinB

=>cos2A=cos(A+A)

=>cos2A=cosA.cosA - sinA.sinA

=>cos2A=cos²A-sin²A

=>cos2A=(cos²A-sin²A)/(cos²A+sin²A

Since {cos²A+sin²A=1}

Divide the numerator & the denominator by (cos²A) to get,

cos2A = {(cos²A-sin²A) ÷cos²A} / {(cos²A+sin²A) ÷cos²A}

cos2A ={(1-tan²A)/(1+tan²A)}

Then,

1-cos2A = 1-[{(1–tan²A)/(1+tan²A)}]

1-cos2A =(1+tan²A-1+tan²A)/(1+tan²A)

1-cos2A=(2tan²A)/(1+tan²A)

And now.......

1+cos2A=1+[{(1-tan²A)/(1+tan²A)}]

1+cos2A={1+tan²A+1-tan²A}/{1+tan²A}

1+cos2A=2/(1+tan²A)

So now,

(1-cos2A)/(1+cos2A)= {2tan²A/(1+tan²A)}÷{2/(1+tan²A)}

={(2tan²A)(1+tan²A)}÷{2(1+tan²A)}

=tan²A

Step-by-step explanation:

make me as brain liest

3 0
4 years ago
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