The problem statement gives you the relationship between their speeds, and it gives you information you can use to find their total speed. You solve this by finding the total speed, then the proportion of that belonging to Bill.
The total speed is (120 mi)/(3 h) = 40 mi/h.
The speed ratio is ...
... Bill : Joe = 3 : 1
so the speed ratio Bill : Total is ...
... 3 : (3+1) = 3:4.
Bill's speed is (3/4)×(40 mi/h) = 30 mi/h.
By multiplying the same numbers.
2*2=4 *4 square root is 2
3*3=9 *9 square root is 3
4*4=16 *16 square root is 4
5*5=25 *25 square root is 5
Try this, maybe it will work :)
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
Answer:
hb=2.5
Step-by-step explanation:
base = 4
area = 5
Answer: see image
<u>Step-by-step explanation:</u>
Draw line x = 3. Count how many units each point is away from line x = 3. Plot the new point the same number of units away from line x = 3 but in the opposite direction.
Point G is 4 units to the left of x = 3. The new point G' is 4 units to the right of x = 3.
Point F is 7 units to the left of x = 3. The new point G' is 7 units to the right of x = 3.
Point E is 7 units to the left of x = 3. The new point G' is 7 units to the right of x = 3.
Point H is 4 units to the left of x = 3. The new point G' is 4 units to the right of x = 3.
