Twice a number is at most 36.
2 answers:
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Answer:
Find the midsegment of the triangle which is parallel to CA.
Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.
We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.
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I'm going to assume the crust covered by the dosenot matter because the total surface area cannot be found without the depth of the pie.
So the surface are is the area of the top of the pie, the top of the pie is circular and is equal to 2
r²
The diameter is the sum of 2 radii, hence r=8
D=12
= 2r =12
r=8
With the raduis the area can be found
A= 2r²
A=28²
A=2(64)
A=128
If the pie cost 10.99, the cost per inch can be found by dividing the area by cost
cost/inch =128/10.99
cost/inch =11.64
= 11.64(3.14)
= 36.57
The pie costs 36 cents per square inch
So the surface are is the area of the top of the pie, the top of the pie is circular and is equal to 2
The diameter is the sum of 2 radii, hence r=8
D=12
= 2r =12
r=8
With the raduis the area can be found
A= 2
A=2
A=2(64)
A=128
If the pie cost 10.99, the cost per inch can be found by dividing the area by cost
cost/inch =128
cost/inch =11.64
= 11.64(3.14)
= 36.57
The pie costs 36 cents per square inch
Solution
Problem 6
For this case we can do this:
12, 16,__, 14, 8, 7
We can solve for x like this:
Problem 7
F