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storchak [24]
3 years ago
6

The right triangle ABC is shown below. Find the missing side by using the Pythagorean theorem,if a=6ft and b=8ft​

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0

Answer:

c = 10 feet.

Step-by-step explanation:

c^2 = a^2 + b^2  (By the Pythagoras Theorem)

c^2 = 6^2 + 8^2 = 100

c + sqrt 100 = 10.

docker41 [41]3 years ago
4 0

Answer:

c = 10

Step-by-step explanation:

Using Pythagoras' theorem

The square on the hypotenuse of a right triangle is equal to the sum of the squares on the other 2 sides, that is

c² = a² + b² ← substitute values

c² = 6² + 8² = 36 + 64 = 100 ( take the square root of both sides )

c = \sqrt{100} = 10

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Answer:

You would use the formula y=mx+b, where m is the slope and b is the y intercept.

Step-by-step explanation:

If the slope was 1/2 and the y intercept was 2, it would be y=1/2x+2

4 0
3 years ago
The perimeter of a rectangular certificate is 28 inches. The area is 48 square inches. What are the dimensions of the certificat
mafiozo [28]
It is 6 and 8 because:
P=6+6+8+8 which is 28
and
A=6×8 which is 48
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3 years ago
An equation of the line tangent to y=sinx+2cosx at (pi/2, 1) is
Sati [7]
Lo que queres es 34  5 5 5
6 0
3 years ago
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
4 years ago
2(8y-7)=2(3+8y)<br>please help I am having trouble ​
KonstantinChe [14]

Answer:

its undefined

Step-by-step explanation:

u dont have enough information ahh

4 0
3 years ago
Read 2 more answers
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