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kogti [31]
3 years ago
12

Help!!!!! Someone please

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Answer:I would say 6 but I could be wrong.

Step-by-step explanation:

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Please help and thank you
ycow [4]

Answer:

D) 130 workers

Step-by-step explanation:

We have the equation, <em>y = 2x + 40</em>, and <em>y, 300</em> (since the y-coordinate represents the # of bottles made), so we can solve for x, <em>the number of workers needed</em>.

Substitute: <em>300 = 2x + 40</em>

Subtract: <em>260 = 2x</em>

Divide: <em>x = 130</em>

Since x = 130 when y = 300, 130 workers are required to make 300 bottles in a day.

4 0
3 years ago
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
the amount of money in an account with continuously compounded interest. calculated to the nearest tenth of a year how long it t
pentagon [3]
You will need this formula:
Years = ln (Total / Principal) / rate
(where "ln" means natural logarithm)
and we'll use $100 and $200 for beginning and ending amount
Years = ln (200 / 100) / rate
Years = 0.69314718056 / .052
Years = <span> <span> <span> 13.3297534723 </span> </span> </span>
Rounding to the nearest tenth of a year:
Years = <span> <span> <span> 13.3

Source:
http://www.1728.org/rate2.htm

</span></span></span>

6 0
3 years ago
What is the HCF of 14 and 21?
Shkiper50 [21]
The highest common factor is seven

8 0
3 years ago
Read 2 more answers
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