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4 years ago

Find percent 15 yards to 18 yards

Mathematics

2 answers:

Katen [24]4 years ago

5 0

The answer is 8.333333333

Rudiy274 years ago

3 0

18/15 = 1.2
Then you have to multiply by 100 to get a %

1.2 x 100%= 120%

The answer is 120%

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The endpoints of one diagonal of a rhombus are (0, -8) and (8, -4). If the coordinates of the 3rd vertex are (1, 0), what are th

xeze [42]

The answer is (-7, -12).

Attached is the graph to show the answer.

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3 years ago

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4|m-n|<br> If m=-7 and n=2

Snowcat [4.5K]

You would first substitute -7 for m and 2 for n. It would look like this: 4| -7-2 | . we first solve the absolute value because it is the first step in PEMDAS or order of operations. -7-2 is equal to -9. Our equation should look like this now: 4 |-9| . we solve the absolute value portion, the absolute value of a negative number is the the same number but positive. the absolute value would be 9. (we just take the negative symbol off). we now have 4 x 9. This is equal to 36.

36 is the answer.

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3 years ago

2. (For this problem, leave your answers in Combinatorics format – do NOT simplify). A conference is being held that faculty mem

SSSSS [86.1K]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

please find the complete question in the attached file.

female = 23 and male = 19 faculty members

Randomly selected member are = 6

In point 1:

The Probability to equally selecting men and women:

$= \frac{(23C3+19C3)}{42C6}$

In point 2:

The Probability of selecting at least 4 men:

$= \frac{((19C4 \times 23C2)+(19C5 \times 23C1)+(19C6))}{42C6}$

In point 3:

The probability in which no women are chosen implies that 6 selected members are from 23 women:

$= \frac{23C6 }{42C6}$

In point 4:

The Probability in which no more than 4 women are selected:

$\frac{((19C6)+(23C1 \times 19C5)+(23C2 \times 19C4)+(23C3 \times 19C3)+(23C4 \times 19C2))}{42C6}$

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3 years ago

Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.

WARRIOR [948]

The polynomial $2x^3 + 5x^2-8x-20$ may have solutions which are the divisors of -20, therefore -20 has the following divisors: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .
If x=1, then $2\cdot1^3 + 5\cdot1^2-8\cdot1-20=-20\neq 0$ ,
if x=-1, then $2\cdot(-1)^3 + 5\cdot(-1)^2-8\cdot(-1)-20=-9\neq 0$ ,
if x=2, then $2\cdot2^3 + 5\cdot2^2-8\cdot2-20=0$ , then x=2 is a solution and you have the first factor (x-2).
If x=-2, then $2\cdot(-2)^3 + 5\cdot(-2)^2-8\cdot(-2)-20=0$ , then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of $2x^3 + 5x^2-8x-20$ , then the polynomial $x^2-4$ is a divisor of $2x^3 + 5x^2-8x-20$ and dividing the polynomial $2x^3 + 5x^2-8x-20$ by $x^2-4$ you obtain
$2x^3 + 5x^2-8x-20=(x-2)(x+2)(2x+5)$ .

5 0

3 years ago

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Help guys, i’m giving you 12 points (:

OleMash [197]

Answer: 31.42 inches

Step-by-step explanation:

Circumference = 2πr

= 2 x 22/7 x 5

= 31.42 inches

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3 years ago

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