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cluponka [151]
3 years ago
11

Someone please tell me what (A) and (X) are and how xxx

Mathematics
1 answer:
azamat3 years ago
6 0
As they are both corresponding angles of 2 parallel lines,the angles will be the same
x=130°
a=60°
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It means the scatter plot is a line with negative slope. The relation is perfectly described by a linear equation.
4 0
3 years ago
X
sergeinik [125]

Answer:

A. x = 58°

B. x = 10m

C. a = 44°

All approximated to nearest whole number.

Step-by-step explanation:

All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.

Recall: SOHCAHTOA

a. Adjacent = 4.8cm,

Hypotenuse = 9cm

Angle to find =x°

Thus, we would apply the following formula:

Cos θ = Adjacent/Hypotenuse

Cos θ = 4.8/9 = 0.5333

θ = Cos-¹(0.5333) = 57.77

x ≈ 58° (to nearest whole number)

b. Opposite side = x

Hypothenuse = 40 m

Included angle = 14°

We would use:

Sine θ = opposite/hypothenuse

Sin (14) = x/40

Multiply both sides by 40

40*sin(14) = x

40*0.2419 = x

x = 9.676 = 10 m (to nearest whole number)

c. Opposite = 87mm

Adjacent = 91mm

θ = a°

We would use:

Tan θ = opposite/adjacent

Tan θ = 87/91

Tan θ = 0.9560

θ = tan-¹(0.9560)

θ = a = 43.71

a ≈ 44° (to nearest whole number)

7 0
3 years ago
If x + y = –10 and x - y = 2, what is the value of x?
luda_lava [24]

Answer:

y -10

x graph

Step-by-step explanation:

5 0
3 years ago
1/3(2x+3)-1/5(x+6)=4
Virty [35]
What are you looking for?
6 0
2 years ago
12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?
mixas84 [53]

Given the equation:

\frac{x}{6}+3=-18

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

\frac{x}{6}+3-(3)=-18-(3)

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

- Add their Absolute values (their values without the negative sign).

- Write the sum with the negative sign.

Then:

\frac{x}{6}=-21

(b) The correct procedure is:

1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\  \\ \frac{x}{6}=-21 \end{gathered}

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\  \\ x=-126 \end{gathered}

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

-18-3=-15\text{ (False)}

(b) The value of "x" should be:

x=-126

4 0
1 year ago
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