Answer:
Type I error occurs when the null hypothesis, H0, is rejected, although it is true.
Here the null hypothesis, H0 is:
H0: Setting weekly scheduled online interactions will boost the well being of people who are living on their own during the stay at home order.
a) A Type I error would be committed if the researchers conclude that setting weekly scheduled online interactions will not boost the well being of people who are living on their own during the stay at home order, but in reality it will
b) Two factors affecting type I error:
1) When the sample size, n, is too large it increases the chances of a type I error. Thus, a sample size should be small to decrease type I error.
2)A smaller level of significance should be used to decrease type I error. When a larger level of significance is used it increases type I error.
I want more points next time....Hehehee!
<h2>
<u>______________________</u></h2>
<em>Solution in attachments!</em>
Answer:
y = -0.25x + 10
Step-by-step explanation:
Point-slope form is y - y1 = m (x - x1)
Here, y1 is 7, m is -0.25, and x1 is 12
When you plug these values in, you get y - 7 = -0.25 (x - 12)
Now we have to solve for y.
y - 7 = -0.25 (x - 12)
Distribute
y - 7 = -0.25x + 3
Add 7 to both sides
y = -0.25x + 10
Answer:
Step 1: Remove parentheses by multiplying factors.
= (x * x) + (1 * x) + (2 * x) + (2 * 1)
Step 2: Combine like terms by adding coefficients.
(x * x) = x2
(1 * x) = 1x
(2* x) = 2x
Step 3: Combine the constants.
(2 * 1) = 2
Step 4: Therefore, Simplifying Algebraic Expression is solved as
= x2 + 3x + 2.
Answer:
Step-by-step explanation:
Let the side of the square base be x
h be the height of the box
Volume V = x²h
13500 = x²h
h = 13500/x² ..... 1
Surface area = x² + 2xh + 2xh
Surface area S = x² + 4xh ...... 2
Substitute 1 into 2;
From 2; S = x² + 4xh
S = x² + 4x(13500/x²)
S = x² + 54000/x
To minimize the amount of material used; dS/dx = 0
dS/dx = 2x - 54000/x²
0 = 2x - 54000/x²
0 = 2x³ - 54000
2x³ = 54000
x³ = 27000
x = ∛27000
x = 30cm
Since V = x²h
13500 = 30²h
h = 13500/900
h = 15cm
Hence the dimensions of the box that minimize the amount of material used is 30cm by 30cm by 15cm
