Answer: the first one is C
the second one is B
Your answer would be c. 18,6
Answer:
The given expression can't be expressed in polynomial form. Hence, it is not a polynomial.
Step-by-step explanation:
P(x,n) is a polynomial of nth degree if it is of the form,
P(x,n) = ![a_{0} + a_{1}x + a_{2}x^{2} + a_{3}x^{3} + ......... +a_{n}x^{n}](https://tex.z-dn.net/?f=a_%7B0%7D%20%2B%20a_%7B1%7Dx%20%2B%20a_%7B2%7Dx%5E%7B2%7D%20%2B%20a_%7B3%7Dx%5E%7B3%7D%20%2B%20.........%20%2Ba_%7Bn%7Dx%5E%7Bn%7D)
where n is a finite positive integer and n ∈ N
and '
's are fixed but otherwise arbitrary constants ∀ i = 0(1)n .
Now, the given expression is,
![9x^{3} + \frac {1}{2x^{2}} + 3x^{-1}](https://tex.z-dn.net/?f=9x%5E%7B3%7D%20%2B%20%5Cfrac%20%7B1%7D%7B2x%5E%7B2%7D%7D%20%2B%203x%5E%7B-1%7D)
which doesn't fit in the above form. Hence, it is not a polynomial.
Answer:
Step-by-step explanation:
Given that a researcher is trying to decide how many people to survey.
We have confidence intervals are intervals with middle value as the mean and on either side margin of error.
Confidence interval = Mean ± Margin of error
Thus confidence interval width depends on margin of error.
Margin of error = ![Critical value *\frac{\sigma}{\sqrt{n} }](https://tex.z-dn.net/?f=Critical%20value%20%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%20%7D)
Thus for the same confidence level and std deviation we find margin of error is inversely proportional to square root of sample size.
Hence for small n we get wide intervals.
So if sample size = 300, the researcher will get wider confidence interval