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Marta_Voda [28]
4 years ago
12

What will happen if there is no mitrochondria in a cell

Biology
1 answer:
amm18124 years ago
7 0
Without mitochondria (singular, mitochondria), higher animas would most likely not exist because their cells would only be able to obtain energy from anaerobic respiration (in the absence of oxygen), a proved much less efficient that aerobic respiration.
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Which organelle is responsible for breaking down the cells that once made up the tail of the tadpole?
yuradex [85]
The correct answer is lysosome! 
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3 years ago
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What is the basic difference between simple diffusion and facilitated diffusion across a cell membrane? hints?
Licemer1 [7]

Simple diffusion is the process by which a substance moves across a cell membrane from an area of high concentration to an area of low concentration. Substances that move by simple diffusion are able to diffuse directly across the phospholipid bilayer of the cell membrane. These substances are generally small and neutral, as large or charged particles cannot cross the phospholipid bilayer. Some examples of molecules that move by simple diffusion are carbon dioxide and oxygen.  

Facilitated diffusion is the process by which a substance moves across a cell membrane from an area of high concentration to an area of low concentration with the aid of a membrane protein. Substances that move by facilitated diffusion are not able to diffuse directly across the phospholipid bilayer of the cell membrane. These substances are generally large and/or charged. They therefore travel through a protein channel in the cell membrane along their concentration gradient. Some examples of substances that can move by facilitated diffusion are glucose, sodium ions and chloride ions.  

The similarities between facilitated diffusion and simple diffusion are:  

They both involve the movement of a substance across a cell membrane along its concentration gradient (from an area of high concentration to an area of low concentration).  

They are both examples of passive transport, as neither requires energy from the cell to move the substance across the membrane.

8 0
3 years ago
The side chain of glutamic acid is an organic acid. Which statement BEST explains the charge of this glutamic acid side chain wh
fiasKO [112]
I think it’s .c I’m not sure
7 0
4 years ago
Can someone Identify the phase
jenyasd209 [6]

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Metaphase of Mitosis

Explanation:

7 0
3 years ago
In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2
Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

r = \frac{1500 - 750}{1995 - 1985}  = 750/10 = 75

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

         area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

         area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

         area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

r = \frac{D(1995) - D(1885)}{1995 - 1985}  = \frac{6 pines/ha - 3pines/ha}{10}  = 0.3 pines/ha

So, on average, each year the number of pines per hectare increases by 0.3

7 0
3 years ago
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