Question

Complete the square to determine the minimum or maximum value of the function defined by the expression.

Answer 1

Answer:

Option B) minimum value at −10

Step-by-step explanation:

we have

$f(x)=x^{2} -10x+15$

This function represent a vertical parabola open upward (because the leading coefficient is positive)

The vertex represent a minimum

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-15=x^{2} -10x$

Divide the coefficient of term x by 2

10/2=5

squared the term and add to the right side of equation

$f(x)-15=(x^{2} -10x+5^2)$

Remember to balance the equation by adding the same constants to the other side

$f(x)-15+5^2=(x^{2} -10x+5^2)$

$f(x)+10=(x^{2} -10x+25)$

rewrite as perfect squares

$f(x)+10=(x-5)^{2}$

$f(x)=(x-5)^{2}-10$ ----> function in vertex form

The vertex of the quadratic function is the point (5,-10)

therefore

The minimum value of the function is -10