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Naily [24]
3 years ago
9

-7x + 13 HELP I WILL CHOOSE BRAINLIEST TO BEST ANSWER

Mathematics
2 answers:
Novay_Z [31]3 years ago
7 0

Answer:

-20x

Step-by-step explanation:

Leni [432]3 years ago
3 0
search it up than you will get the correct answer
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When Kaitlin divided a fraction by 1/2 the result was a mixed number. Was the original fraction less than or greater than 1/2?
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5 0
4 years ago
Please help me!!!
Juli2301 [7.4K]
Well, the general form for point-slope form is y-ysub1= m(x-xsub1). In the general form,  ysub1 stands for the y-coordinate and xsub1 stands for the x-coordinate, and m stands for the slope. When writing in point-slope form, we need the slop and one ordered pair. 

The equation has already given us two ordered pairs but it doesn't give us the slope. We just need to find the slope between these two points, which is 3/1, or just 3. Then we pick one of the ordered pair they gave us and plug in the general form. 

I'll go with the first ordered pair, (2,1). The y and the x in the equation, don't plug them in, leave them as it is, we only need to plug in the slope and the two coordinates. So we get y-1=3(x-2). 

I'll only do the first ordered pain for you, and you should be able to do the second one.
8 0
3 years ago
A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
attashe74 [19]

Answer:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

X= 36 represent the families owned at least one DVD player

n= 85 represent the total number of families

\hat p=\frac{36}{85}= 0.424 represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

8 0
3 years ago
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