Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Sure but wheres the picture?
Answer:
Option C. 
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The intersection point is (1,3)
see the attached figure
therefore
The solution of the system of equations is

Find the difference
