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skelet666 [1.2K]
2 years ago
14

14. Choose the best description of the polynomial:

Mathematics
1 answer:
Anvisha [2.4K]2 years ago
8 0
C as there are only 3 terms tip- (count how many symbols). And the highest power it goes to is 2 so it’s 5y squared. Hope this helps :)
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28% of what number is 63
Scrat [10]
We set up a proportion: 63/?= 28/100

Cross multiply: 28*?= 63*100
⇒ ?= 63*100/28= 225

28% of 225 is 63.
6 0
3 years ago
Read 2 more answers
Select all of the terms that are "like."<br><br> xy2<br> 2xy<br> x2<br> -xy<br> 2x2y<br> 1/2xy
irakobra [83]
Hi,
The like terms are 2xy, -xy and (1/2)xy, since they have the same variables and powers.
4 0
3 years ago
Which expression is equal to the expression below (6x9)^5
masha68 [24]

Answer:

B. You have to distribute properties. So you distribute the exponent 5 to both the 6 & the 9

4 0
3 years ago
Need Answered ASAP
kicyunya [14]

Answer:

The possible rational roots are: +1, -1 ,+3, -3, +9, -9

Step-by-step explanation:

The Rational Root Theorem tells us that the possible rational roots of the polynomial are given by all possible quotients formed by factors of the constant term of the polynomial (usually listed as last when written in standard form), divided by possible factors of the polynomial's leading coefficient. And also that we need to consider both the positive and negative forms of such quotients.

So we start noticing that since the leading term of this polynomial is x^3, the leading coefficient is "1", and therefore the list of factors for this is: +1, -1

On the other hand, the constant term of the polynomial is "9", and therefore its factors to consider are: +1, -1 ,+3, -3, +9, -9

Then the quotient of possible factors of the constant term, divided by possible factor of the leading coefficient gives us:

+1, -1 ,+3, -3, +9, -9

And therefore, this is the list of possible roots of the polynomial.

6 0
3 years ago
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
3 years ago
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