Question

Find all values of $x$ such that $3x^2 + 16x + 5=0$. If you find more than one value, then list your solutions, separated by commas.

Answer 1

answer

x = {-5, -⅓}

explanation

$3 {x}^{2} + 16x + 5 = 0$

$3 {x}^{2} + 15x + x + 5 = 0$

$3x(x + 5) + 1(x + 5) = 0$

$(x + 5)(3x + 1) = 0$

$x = - 5 \: or \: - \frac{1}{3}$

$x = \{ - 5 \: , - \frac{1}{3} \}$

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