Y = mx + b slope(m) = 3/4 (3,7)...x = 3 and y = 7 now we sub and find b, the y int 7 = 3/4(3) + b 7 = 9/4 + b 7 - 9/4 = b 28/4 - 9/4 = b 19/4 = b
so ur equation is : y = 3/4x + 19/4
if point A (x,5) lies on the line..... y = 3/4x + 19/4......when y = 5 5 = 3/4x + 19/4 5 - 19/4 = 3/4x 20/4 - 19/4 = 3/4x 1/4 = 3/4x (1/4) / (3/4) = x 1/4 * 4/3 = x 4/12 reduces to 1/3 = x......so point A is (1/3,5)...with x being 1/3
∠JAL is 65° because vertical angle to ∠IAK So angle ∠JAE is 90° - 65° (total angle measure is 90°) ∠JAE is 25° Therefore ∠ACB is also 25° because alternate interior angles And ∠JCG is 25° because vertical angles
