The converse of the statement would be
"If x ≤ 7, then x² ≤ 49"
but this is false. Take x = -8; while it's true that -8 ≤ 7, the second inequality is not, since (-8)² = 64 is not smaller than 49.
Answer:
What is the question?
Step-by-step explanation:
Answer:
-k-h/r-s
When solving the goal is to get x on one side and not x on the other.
rx + h = sx - k
rx - sx + h = -k <------- subtract sx from both sides
rx - sx = -k - h <-------subtract h from both sides
x (r - s) = -k -h <------factor out x which is in both rx and sx
x = - k - h / r - s <-------divide by r-s on both sides
