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mihalych1998 [28]
3 years ago
13

During a clothing store’s Bargain Days, the regular price for T-shirts is discounted by $5. There is a state sales tax of 5%, an

d the $5 discount is applied before the sales tax is calculated.
a. Write an expression that shows the regular price r of a T-shirt minus the $5 discount.

b. Write a rule for the function p(r) that expresses the final price p of a T-shirt with the discount applied and sales tax added.

c. How much would you pay during Bargain Days for a shirt regularly priced at $15.50?
Mathematics
2 answers:
ser-zykov [4K]3 years ago
8 0
A) d = r - 5 where t is the full price 
<span>b) p = ( r - 5 ) * 1.05 </span>
<span>c) p = (15.5-5)*1.05 = 10.5 * 1.05 = $ 11.02</span>
zavuch27 [327]3 years ago
6 0

Answer:

A:

Let the regular price of the t shirt be = r

Let the total cost of the t shirt be = t

So, we can say : t=r-5

B:

p(r)=1.05(r-5)

C:

p(r)=1.05(r-5)

Substituting r = 15.50

p(r)=1.05(15.50-5)

=> p(r)=1.05(10.50)

= $11.025

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Step-by-step explanation:

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Find the value of c that makes each trinomial a perfect square.
gavmur [86]

Answer:

The answer to your question is the letter a.

Step-by-step explanation:

Data

             x² + 12x + c

If this trinomial is a perfect square trinomial, the third term must be half the second term divided by the square root of the first term, and to the second power.

-Get half the second term

               12x/2 = 6x

-Divide by the square root of the first term

               6x/x = 6

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6 0
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What is the domain of the function graphed below?
WITCHER [35]

From the graph, the domain of the function will be {x| x = −2,1}. Then the correct option is D.

<h3>What is an asymptote?</h3>

An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.

From the graph, the domain of the function will be

The function is not defined for x = 2 and x = -1.

Then the domain will be

{x| x = −2,1}

Then the correct option is D.

More about the asymptote link is given below.

brainly.com/question/17767511

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A bottled water distributor wants to determine whether the mean amount of water contained in 1-gallon bottles purchased from a n
mash [69]

Answer:

We fail to reject H0; Hence, we conclude that there is no significant evidence that the mean amount of water per gallon is different from 1.0 gallon

Pvalue = - 2

(0.98626 ; 1.00174)

Since, 1.0 exist within the confidence interval, then we can conclude that mean amount of water per gallon is 1.0 gallon.

Step-by-step explanation:

H0 : μ= 1

H1 : μ < 1

The test statistic :

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(0.994 - 1) / (0.03/sqrt(100))

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The Pvalue :

Pvalue form Test statistic :

P(Z < - 2) = 0.02275

At α = 0.01

Pvalue > 0.01 ; Hence, we fail to reject H0.

The confidence interval :

Xbar ± Margin of error

Margin of Error = Zcritical * s/sqrt(n)

Zcritical at 99% confidence level = 2.58

Margin of Error = 2.58 * 0.03/sqrt(100) = 0.00774

Confidence interval :

0.994 ± 0.00774

Lower boundary = (0.994 - 0.00774) = 0.98626

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