Step-by-step explanation:
20%=cows 0.4(40%)=goat 40%=sheep
if 40%sheep=40 sheeps
20% cow=x
20%×40=40%×x
8=40%x
x=8/40%
x=20
..so there are 20 cows
sorry...not sure
The answer would be true because 4+5 is > 8
Answer:
The answer to your question is the letter a.
Step-by-step explanation:
Data
x² + 12x + c
If this trinomial is a perfect square trinomial, the third term must be half the second term divided by the square root of the first term, and to the second power.
-Get half the second term
12x/2 = 6x
-Divide by the square root of the first term
6x/x = 6
-Express the result to the second power
6² = 36
-Write the perfect square trinomial
(x² + 12x + 36) = (x + 6)²
From the graph, the domain of the function will be {x| x = −2,1}. Then the correct option is D.
<h3>What is an asymptote?</h3>
An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.
From the graph, the domain of the function will be
The function is not defined for x = 2 and x = -1.
Then the domain will be
{x| x = −2,1}
Then the correct option is D.
More about the asymptote link is given below.
brainly.com/question/17767511
#SPJ1
Answer:
We fail to reject H0; Hence, we conclude that there is no significant evidence that the mean amount of water per gallon is different from 1.0 gallon
Pvalue = - 2
(0.98626 ; 1.00174)
Since, 1.0 exist within the confidence interval, then we can conclude that mean amount of water per gallon is 1.0 gallon.
Step-by-step explanation:
H0 : μ= 1
H1 : μ < 1
The test statistic :
(xbar - μ) / (s / sqrt(n))
(0.994 - 1) / (0.03/sqrt(100))
-0.006 / 0.003
= - 2
The Pvalue :
Pvalue form Test statistic :
P(Z < - 2) = 0.02275
At α = 0.01
Pvalue > 0.01 ; Hence, we fail to reject H0.
The confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * s/sqrt(n)
Zcritical at 99% confidence level = 2.58
Margin of Error = 2.58 * 0.03/sqrt(100) = 0.00774
Confidence interval :
0.994 ± 0.00774
Lower boundary = (0.994 - 0.00774) = 0.98626
Upper boundary = (0.994 + 0.00774) = 1.00174
(0.98626 ; 1.00174)