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KonstantinChe [14]
3 years ago
7

Find the radius of each figure. round to the nearest tenth.

Mathematics
1 answer:
k0ka [10]3 years ago
6 0

Answer:

8.25475 m

Step-by-step explanation:

pi*r^3 is the formula for a sphere.


Using this, pi is a nmber (about 3.14) and we only don't know the radius, but we know what it equals.


pi*r^3=1,767.1

First divide by pi, then get ride of the cube by cube rooting both sides.


The cube root of 1767.1/pi (remember to cube root both denominator and numberator!!!) is about 8.25475 m

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Graph the system of equations on your graph paper to answer the question.
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(-2,3)

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3 years ago
What will be the index of 2 for its value equal to 1/2​
Art [367]

Answer:

the index of 2 is -1

Step-by-step explanation:

2^{-1}

=\frac{1}{2^1}

=\frac{1}{2}

3 0
3 years ago
Which is more, 3 pounds or 50 ounces?
Luba_88 [7]

50 ounces = 3.125 pounds Alternative conversion We can also convert by utilizing the inverse value of the conversion factor. In this case 1 pound is equal to 0.32 × 50 ounces. hope this helps you!! <3

6 0
2 years ago
Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
kvv77 [185]

The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
  • The value of c(n(100)) is \mathbf{c(n(100)) = 130000}
  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

<u>(b) Function c(n(h))</u>

In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0
3 years ago
Find the sum of the arithmetic series...........<br> 3 + 5 + 7 + 9 + 11 + for 100 terms.
tatyana61 [14]

Answer:

Step-by-step explanation:

3 + 5 +7 +9 + 11 + ....

n = 100

a = 3

d = 5 - 3 = 2

S_{n}=\frac{n}{2}(2a + (n-1)d)\\\\S_{100}=\frac{100}{2}(2*3+99*2)\\\\=50*(6+198)\\\\= 50 * 204\\= 10200\\

4 0
3 years ago
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