All categories

2 years ago

Find the radius of each figure. round to the nearest tenth.

Mathematics

1 answer:

k0ka [10]2 years ago

6 0

Answer:

8.25475 m

Step-by-step explanation:

pi*r^3 is the formula for a sphere.

Using this, pi is a nmber (about 3.14) and we only don't know the radius, but we know what it equals.

pi*r^3=1,767.1

First divide by pi, then get ride of the cube by cube rooting both sides.

The cube root of 1767.1/pi (remember to cube root both denominator and numberator!!!) is about 8.25475 m

You might be interested in

Help me with my math please

monitta

Answer:

Volume of a cylinder = πr²h

Given

V=81π

r=3

find h

Making h the subject

h= V/πr² = 81π/π(3)²

h= 81/9

h= 9cm

3 0

3 years ago

Read 2 more answers

A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR? pythagorus theorem

algol13

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

by using Pythagoras law

h²=p²+b²

80²=QR²+60²

QR²=80²-60²

QR= $\sqrt{2800}$

QR=20 $\sqrt{7}$ =52.9=53cm

QR=53cm.

5 0

3 years ago

Adding fractions 1/6+2/3=

mars1129 [50]

Answer:

$\frac{5}{6}$

$\frac{1}{6} + \frac{2}{3}$ is equivalent to $\frac{1}{6} + \frac{4}{6}$ .

This is because $\frac{2}{3}=\frac{4}{6}$

The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

Now what do we do? We add!

$\frac{1}{6} + \frac{4}{6} =\frac{5}{6}$

This is because 4 + 1 = 5.

Your answer is $\frac{5}{6}$ .

I hope this helps!

<h2>PLEASE MARK BRAINLIEST!</h2>

8 0

3 years ago

Read 2 more answers

(9 x 10) + (20x + 21) = 571 What does (x) equal

creativ13 [48]

(9 × 10) + (20x + 21) = 571
90 + 20x + 21 = 571
111 + 20x = 571
- 111
20x = 460
÷ 20
x = 23
I hope this helps!

8 0

2 years ago

Read 2 more answers

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0

2 years ago