4^4x-5= 8^3x-4 solve

1 answer:

8 0

$4^{4x-5}=8^{3x-4}\\\\(2^2)^{4x-5}=(2^3)^{3x-4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\2^{2(4x-5)}=2^{3(3x-4)}\iff2(4x-5)=3(3x-4)\qquad\text{use distributive property}\\\\(2)(4x)+(2)(-5)=(3)(3x)+(3)(-4)\\\\8x-10=9x-12\qquad\text{add 10 to both sides}\\\\8x=9x-2\qquad\text{subtract 9x from both sides}\\\\-x=-2\to \boxed{x=2}$

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