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Leokris [45]
3 years ago
5

4^4x-5= 8^3x-4 solve

Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0

4^{4x-5}=8^{3x-4}\\\\(2^2)^{4x-5}=(2^3)^{3x-4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\2^{2(4x-5)}=2^{3(3x-4)}\iff2(4x-5)=3(3x-4)\qquad\text{use distributive property}\\\\(2)(4x)+(2)(-5)=(3)(3x)+(3)(-4)\\\\8x-10=9x-12\qquad\text{add 10 to both sides}\\\\8x=9x-2\qquad\text{subtract 9x from both sides}\\\\-x=-2\to \boxed{x=2}

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The diameter of a circle has length 12. The center is at*(-5, 2). Give the equation
labwork [276]

Answer:

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Step-by-step explanation:

Let us consider the image attached in the answer area.

The center<em> O</em> has the co-ordinates i.e. <em>(-5,2)</em> and the diameter given is <em>12 units</em>.

We know that radius is half of diameter.

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Where <em>(a,b)</em> is the co-ordinate of center and <em>r</em> is the radius.

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