Step-by-step explanation:
F(x) = ∫ₐˣ t⁷ dt
F(x) is the area under f(t) between t=a and t=x. When x=a, the width of the interval is 0, so the area is zero.
F(6) = 0, so a = 6.
F(x) = ∫₆ˣ t⁷ dt
F(6) = ∫₆⁶ t⁷ dt
F(6) = 0
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Answer: X- 0,1,2,3,4 and Y-0,6,12,18,24
Step-by-step explanation: i had to take this test ): luck
Answer:
Step-by-step explanation:
My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.
Hello and Good Morning/Afternoon:
<u>Let's take this problem step-by-step</u>:
<u>What does the information want:</u>
<u>Let's gather some information</u>:
- ΔA'BC' and ΔABC are similar triangles
⇒ Angle B is shared by both triangles
⇒ Angle A' and A are the same, as they are both on parallel
lines, A'C' and AC, and both angles are formed with the
same line AB
⇒ by the <em>Angle-Angle Theorem*</em>, they are similar triangles
<u>If they are similar triangles</u>:
⇒ their side lengths are proportional to each other
⇒ let's set up a proportion

⇒ let's set up a proportion

<u>Answer:</u>
- <u>x= 17.143</u>
- <u>y = 26.25</u>
Hope that helps!
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