Answer:
765 is divisible by 3 and 9 I hope that this helps
Step-by-step explanation:
765÷9=85
765÷3=255
Answer:
Y(n) = 7n + 23
Step-by-step explanation:
Given:
f(0) = 30
f(n+1) = f(n) + 7
For n=0 : f(1) = f(0) + 7
For n=1 : f(2) = f(1) + 7
For n=2 : f(3) = f(2) + 7 and so on.
Hence the sequence is an arithmetic progression with common difference 7 and first term 30.
We have to find a general equation representing the terms of the sequence.
General term of an arithmetic progression is:
T(n) = a + (n-1)d
Here a = 30 and d = 7
Y(n) = 30 + 7(n-1) = 7n + 23
Answer:
x=31 is the required number.
Step-by-step explanation:
Let the number be represented as "x".
Then, According to the statement given, "x" exceeds by as much as 44 exceed the number, then the equation can be written as:
⇒
⇒
⇒
⇒
Hence, the required number is x =31.
AB + C
= (x + 1)(x^2 + 2x - 1) + 2x
= x^3 + 2x^2 - x + x^2 + 2x - 1 + 2x
= x^3 + 3x^2 + 3x - 1
