Let's start from the left side, and manipulate it to get the right side, which would prove the identity.
We know that:
i)

ii)

.
From the above fundamental identities, we can rewrite the left hand side as:


,
which is what we needed to show.
Answer:
47523.84
Step-by-step explanation:
Do 3 times the length. Suppose the width is 12 centimeters, 3 times that is 36 centimeters plus 4 centimeters is 40 centimers so then you do 2w+2l
well, since we know the endpoints for the diameter, its midpoint will be where the center of the circle is located, so

and if we get the distance between those endpoints, and take half of that, that'd be the radius of it.
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{11})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-4 - (-10)]^2 + [11 - 5]^2}\implies d=\sqrt{(-4+10)^2+6^2} \\\\\\ d=\sqrt{6^2+6^2}\implies d=\sqrt{72}~\hfill \stackrel{radius=half~that}{\cfrac{\sqrt{72}}{2}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-10%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-4%7D~%2C~%5Cstackrel%7By_2%7D%7B11%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Bdiameter%7D%7Bd%7D%3D%5Csqrt%7B%5B-4%20-%20%28-10%29%5D%5E2%20%2B%20%5B11%20-%205%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%28-4%2B10%29%5E2%2B6%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B6%5E2%2B6%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B72%7D~%5Chfill%20%5Cstackrel%7Bradius%3Dhalf~that%7D%7B%5Ccfrac%7B%5Csqrt%7B72%7D%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-7}{ h},\stackrel{8}{ k})\qquad \qquad radius=\stackrel{\frac{\sqrt{72}}{2}}{ r} \\\\\\\ [x-(-7)]^2~~ + ~~[y-8]^2~~ = ~~\left( \frac{\sqrt{72}}{2} \right)^2\implies (x+7)^2~~ + ~~(y-8)^2~~ = ~~18](https://tex.z-dn.net/?f=%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%20%5Cqquad%20center~~%28%5Cstackrel%7B-7%7D%7B%20h%7D%2C%5Cstackrel%7B8%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20radius%3D%5Cstackrel%7B%5Cfrac%7B%5Csqrt%7B72%7D%7D%7B2%7D%7D%7B%20r%7D%20%5C%5C%5C%5C%5C%5C%5C%20%5Bx-%28-7%29%5D%5E2~~%20%2B%20~~%5By-8%5D%5E2~~%20%3D%20~~%5Cleft%28%20%5Cfrac%7B%5Csqrt%7B72%7D%7D%7B2%7D%20%5Cright%29%5E2%5Cimplies%20%28x%2B7%29%5E2~~%20%2B%20~~%28y-8%29%5E2~~%20%3D%20~~18)
Answer:
48nc
Step-by-step explanation:
The LCD of one expression is the expression itself.