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Tom [10]
3 years ago
14

How do i solve it pleas don't give the answer but give hints

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0

Step-by-step explanation:

A mixed number consists of an integer and a proper fraction:

a\frac{b}{c}

where the numerator is less than the denominator (b < c).

A terminating decimal is a decimal that ends.  For example, 1/2 = 0.5.

A repeating decimal is a decimal that repeats forever.  For example, 1/3 = 0.33333...

You must use 2, 3, and 4 exactly once.  Try different combinations and see which ones result in a terminating decimal, and which one results in a repeating decimal.

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In this figure, AB¯¯¯¯¯∥CD¯¯¯¯¯ and m∠1=110°. What is m∠5? Enter your answer in the box.
loris [4]

Answer:

m∠5=110°

Step-by-step explanation:

if 1 is on top line of A and 5 is on the top line of C that would make it corresponding angles pairs that are congruent which they have the same measure so if   m∠1=110° than m∠5=110°

6 0
3 years ago
Please help<br><br> Find the equation of this line.<br> 1<br> a<br> [?]<br> x + [ ]<br> y =
dezoksy [38]
Start by finding the slope.

Pick 2 points on the line and find the “rise” and “run” between them.

To get from (0,3) to (4,0), you’d need to go “down 3” and “right 4”.

Since the slope is “rise over run” and a rise of “down 3” means a rise of “-3”, your slope is -3/4.

Next find the y-intercept: (0,3)
Use the 3 as your b-value for the slope-intercept form.

y=mx+b becomes y= -3/4 x + 3
6 0
3 years ago
n operator in the plant has a monthly salary of $3,200. Thirty-three percent (33%) of her salary is deducted for income tax. How
icang [17]
To find out we need to do

(3,200*33)/100=105,600/100=1,056
 is the third choice
3 0
4 years ago
<img src="https://tex.z-dn.net/?f=x%5E%7B-1%7D" id="TexFormula1" title="x^{-1}" alt="x^{-1}" align="absmiddle" class="latex-form
LenaWriter [7]
True
When multiplying exponents with the same base you add the exponents
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3 0
3 years ago
What to do if quadratic equation has a negative spuare root?
alex41 [277]

If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 3+\sqrt{5}

then 3-\sqrt{5} will also be a solution.

3 0
4 years ago
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