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Sholpan [36]
3 years ago
7

Solve for x! thanks​

Mathematics
1 answer:
MissTica3 years ago
5 0
8 because 180-125 =55
55-15=40
40 divided by 5 is 8
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Mitchell went on a shopping trip to Kensington. He purchased a pair of headphones originally priced at $50 but discounted 60%. I
MrRa [10]

Answer:

$24.50

Step-by-step explanation:

60% of $50= $30

$50-$30= $20

15% of $20= $4.50

$20+$4.50= $24.50

8 0
2 years ago
Read 2 more answers
When AB=3x+8 and GJ=2x+24 what is AB?
valina [46]

Answer:

AB= GJ ➗2

2x+24➗2= x+12

i'm not sure

4 0
3 years ago
Please help me with this. I'll mark brainiest
atroni [7]

Answer:

Option 3 (C)

Step-by-step explanation:

Given the scores of the students: 3, 4, 4, 5, 5, 6, 8, 10, 10, 12, 15, 18

To find the box plot that represents the data set, we need to find:

Min, Q1, median, Q3, and Max, which are all represented on a box plot.

Min = 3

Max = 18

Median = the average of the 6th and 7th data value = (6+8)/2 = 14/2 = 7

Q1 = the average of the 3rd and 4th data values = (4+5)/2 = 4.5

Q3 = the average of the 9th and 10th data values = (10+12)/2 = 11

The box plot that closely represented all these values is the box plot in option 3.

8 0
3 years ago
What is 90 divided by 2
Anon25 [30]
90 ÷ 2 is the same as 1/2 of 90.

Either way you get 45.
7 0
3 years ago
Read 2 more answers
What is the surface area of a sphere with a radius of 12 units?
dexar [7]

          - - - - - -- - - - -- - - - - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - - - -

\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

What is the volume of a sphere with a radius of 12 units?

\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}

\sf{Formula \ for \ Volume \ of \ a \ sphere \ : \bigstar\boxed{\bold{V=\displaystyle\frac{4}{3} \pi r^3}}

Where

\tt{V=Volume}\\\tt{\pi =pi}\\\tt{r=radius}

Provided Information:-

\tt{r=12\:units}

Plug in:-

\bold{V=\displaystyle\frac{4}{3} \pi (12)^3}

\bold{V=\displaystyle\frac{4}{3} \pi (1,728)}

On further simplification,

\dashrightarrow\boxed{\boxed{\underline{\bold{V=2304\pi\:m^3}}}}\dashleftarrow

<h3>Good luck.</h3>

         -- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - -

5 0
2 years ago
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