Answer:
1/9 is probably most likely the correct answer
Answer:
<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>
Step-by-step explanation:
<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14
<em>2. Now let us break this expression into groups: </em>
3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )
<em>3. Factor 3y from 3y^2 - 6y:</em>
3y^2 - 6y ⇒ 3y( y - 2 )
<em>4. Factor 7 from 7y - 14:</em>
7y - 14 ⇒ 7( y - 2 )
<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>
3y( y - 2 ) + 7( y - 2 )
<em>6. Factor common term y - 2:</em>
<em>Answer: ( y - 2 )( 3y + 7 )</em>
Answer:
42
Step-by-step explanation:
weight of medals:
30 (0,5) = 15 kg
cost of 5 kg:
28/2 = 14
cost of shipping:
14+28=42
If you would like to solve the equation 4/5 * x = 2/5, you can calculate this using the following steps:
4/5 * x = 2/5 /*5
4 * x = 2 /4
x = 2/4
x = 1/2
The correct result would be 1/2.
Answer:
Amount of gas that can be hold by Joe's tank = 16 gallons.
Step-by-step explanation:
Given that Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. Now we need to find about how many gallons can Joe's tank hold.
So let's find change that happened after filling the gas.
Change = (5/8 full) - (1/4 full)
Change = (5/8 - 1/4) full
Change = (5/8 - 2/8) full
Change = (5 - 2)/8 full
Change = 3/8 full
So that means 3/8 full happens in 6 gallons
then 1 full will happen in 6/(3/8) gallons = 6*(8/3) gallons = 48/3 gallons = 16 gallons
So the amount of gas that can be hold by Joe's tank = 16 gallons.
