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MaRussiya [10]
3 years ago
7

Which of the equations listed below are linear equations?

Mathematics
2 answers:
telo118 [61]3 years ago
8 0

Answer:

iK ITS A TRICKY QUESTION ITS C THOUGH

Step-by-step explanation:

tangare [24]3 years ago
5 0

Answer:

A. equation I only.

Step-by-step explanation:

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a total of 582 tickets were sold for the school play. they were with adult tickets or student tickets. there were 68 fewer stude
topjm [15]

Answer:

257 adult tickets

Step-by-step explanation:

Let x be the total sold adult ticket.

Given:

Total 582 tickets were sold.

There were 68 fewer student tickets sold than adult tickets

Then there were x-68 students.

So, The total sold ticket equation is

x+(x-68)=582

2x-68=582

2x=582-68

x=\frac{514}{2}

x=257

Therefore, 257 adult tickets were sold

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3 years ago
A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

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3 years ago
What is the approximate area of the circle, in square centimeters? Use 3.14 for π (pi). Record your answer on the grid. then fil
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