Question

If the radius of the base of the cone is 8/3 units and the height is 12 units, what is the volume?

Answer 1

Answer:

89.32

Step-by-step explanation:

The volume of a cone with radius 8/3 and height 12 is

$V= \frac{1}{3}\pi r^2 h= \frac{1}{3}\pi (\frac{8}{3}^2)(12) = \frac{1}{3}\pi (\frac{64}{9})(12)= \frac{1*64*12}{3*9}\pi = \frac{256}{9} \pi = 89.32$.