Use the point-slope formula for the eqn of a str line:
y-1 = 2(x-1)
This becomes y = 1+2(x-1) = 1 + 2x - 2 = 2x - 1,
so the simplest form of the desired eqn is y = 2x - 1.
        
             
        
        
        
One point of the line is given to be (5, -1) and second point is the y-intercept of the line x - 3y = 6
We can write this equation as:

So, the y-intercept of the line is -2. 
Now we have two points for the new line (5, -1) and (0, -2). Using these we can find the slope

Using the slope and the point (0, -2) we can write the equation in slope intercept form as:
 Thus the answer to this question is option C. Slope for the new line is 1/5 and the y-intercept is -2
Thus the answer to this question is option C. Slope for the new line is 1/5 and the y-intercept is -2
 
        
        
        
Answer:
a = 0, b = -15
Step-by-step explanation:
Given two complex number Z1=3cispi and z2=5cis(pi/2)
In polar form;
z1 = 3(cospi + isinpi)
z1 = 3(-1+i0)
z1 = -3+0i
Z2 =  5(cospi/2 + isinpi/2)
Z2 = 5(0+i)
Z2 = 0+5i
Z1*Z2 =  (-3+0i)(0+5i)
Z1*Z2 = 0 - 15i +0i + 0i²
Z1*Z2 = 0-15i
comparing 0-15i with a + bi;
a = 0 and b = -15
 
        
             
        
        
        
Answer:
interesting
Step-by-step explanation: