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denpristay [2]
3 years ago
14

Factor the expression 15x-^2-10x-5

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
15x^2-10x-5=0\\ \\ a=15, \ \ b=-10 \ \ c=-5\\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4* 15* (-5)= 100+300=400\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- \sqrt{400}}{2*15}=\frac{10-20}{30}= \frac{-10}{30}=-\frac{1}{3}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ \sqrt{400}}{2*15}=\frac{10+20}{30}= \frac{30}{30}=1 \\ \\ \ 15x^2-10x-5=15(x+ \frac{1}{3})(x-1)=  (15x+ \frac{1}{3}*15)(x-1)=(15x+5)(x-1)\\ \\ Answer :15x^2-10x-5 =(15x+5)(x-1)
slava [35]3 years ago
6 0
15x^2 - 10x - 5
(3x + 1) (5x - 5)

If it tells you to solve it, set each part in parentheses and solve. What you end up will be your 2 final answers.
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How is place value used to model and find products when multiplying 2 digit numbers?
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Answer:

1 x 4=4 (Both numbers are in the ones place, so their value are ones.)

Step-by-step explanation

In order to use place value to multiply, we use the distributive property to break apart each place. Always begin with the ones place. We can break apart a 2-digit by 1-digit number into 2 simpler problems. 1 x 4=4 (Both numbers are in the ones place, so their value are ones.)

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Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
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The given function is

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\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

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Read 2 more answers
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Answer:

(a) Unit = \frac{1}{4}/8

Step-by-step explanation:

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Required

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Unit = \frac{Time}{Lap}

Substitute values for Time and Lap

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2 years ago
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